list initialization
From cppreference.com
Initializes an object from braced-init-list
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[edit] Syntax
T object { arg1, arg2, ... };
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T { arg1, arg2, ... };
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new T { arg1, arg2, ... };
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return { arg1, arg2, ... } ;
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function( { arg1, arg2, ... } ) ;
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object[ { arg1, arg2, ... } ] ;
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T( { arg1, arg2, ... } )
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Class { T member = { arg1, arg2, ... }; };
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Class:: Class() : member{ arg1, arg2, ...} {...
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T object = { arg1, arg2, ...};
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[edit] Explanation
List initialization is performed in the following situations:
1) initialization of a named variable with a brace-enclosed list of expressions or nested lists (braced-init-list)
2) initialization of an unnamed temporary with a braced-init-list
3) initialization of an object with dynamic storage duration with a new-expression, where the initializer is a brace-init-list
4) in a return statement with braced-init-list used as the return expression
5) in a function call expression, with braced-init-list used as an argument
6) in a subscript expression with a user-defined operator[]
7) in a functional cast expression or other direct-initialization, with braced-init-list used as the constructor argument
8) in a non-static data member initializer
9) in a constructor initializer list
10) on the right-hand-side of the equals sign (similar to copy-initialization)
The effects of list initialization of an object of type T
are:
- If the braced-init-list is empty and
T
is a class type with a default constructor, value-initialization is performed.
- Otherwise, if
T
is an aggregate type, aggregate initialization is performed.
- Otherwise, if
T
is a specialization of std::initializer_list, a newstd::initializer_list
object of the same type is constructed and used to direct-initialize or copy-initialize the object of typeT
, depending on context.
- Otherwise, the constuctors of
T
are considered, in two phases:
-
- All constructors that take std::initializer_list as the only argument, or as the first argument if the remaining arguments have default values, are examined, and matched by overload resolution against a single argument of type std::initializer_list
-
- If the previous stage does not produce a match, all constructors of
T
participate in overload resolution against the set of arguments that consists of the elements of the braced-init-list, with the restriction that only narrowing conversions are allowed. If this stage produces an explicit constructor as the best match for a copy-list-initialization, compilation fails (note, in simple copy-initialization, explicit constructors are not considered at all)
- If the previous stage does not produce a match, all constructors of
- Otherwise, if
T
is reference type, a prvalue temporary of the referenced type is list-initialized, and the reference is bound to that temporary.
- Otherwise, if the braced-init-list has only one element,
T
is direct-initialized or copy-initialized, depending on context, except that narrowing conversions are not allowed.
- Otherwise, if the braced-init-list has no elements,
T
is value-initialized.
[edit] Narrowing conversions
list-initialization limits the allowed implicit conversions by prohibiting the following:
- conversion from a floating-point type to an integer type
- conversion from a long double to double or to float and conversion from double to float, except where the source is a constant expression whose value can be stored exactly in the target type
- conversion from integer or unscoped enumeration type to integer type that cannot represent all values of the original, except where source is a constant expression whose value can be stored exactly in the target type
[edit] Notes
Braced-init-list is not an expression and has no type on its own: for example, when calling a function template, braced-init-list argument cannot be used for template type deduction. A special exception is made for the keyword auto, which deduces any braced-init-list as std::initializer_list.
[edit] Example
#include <iostream> #include <vector> #include <map> #include <string> struct Foo { std::vector<int> mem = {1,2,3}; // list-initialization of a non-static member std::vector<int> mem2; Foo() : mem2{-1, -2, -3} {} // list-initialization of a member in constructor }; std::pair<std::string, std::string> f(std::pair<std::string, std::string> p) { return {p.second, p.first}; // list-initialization in return statement } int main() { int n0{}; // value-initialization (to zero) int n1{1}; // direct-list-initialization std::string s1{'a', 'b', 'c', 'd'}; // initializer-list constructor call std::string s2{s1, 2, 2}; // regular constructor call std::string s3{0x61, 'a'}; // initializer-list ctor is preferred to (int, char) int n2 = {1}; // copy-list-initialization double d = double{1.2}; // list-initialization of a temporary, then copy-init std::map<int, std::string> m = { // nested list-initialization {1, "a"}, {2, {'a', 'b', 'c'} }, {3, s1} }; std::cout << f({"hello", "world"}).first // list-initialization in function call << '\n'; const int (&ar)[2] = {1,2}; // binds a lvalue reference to a temporary array int&& r1 = {1}; // binds a rvalue reference to a temporary int // int& r2 = {2}; // error: cannot bind rvalue to a non-const lvalue ref // int bad{1.0}; // error: narrowing conversion unsigned char uc1{10}; // okay // unsigned char uc2{-1}; // error: narrowing conversion Foo f; std::cout << n0 << ' ' << n1 << ' ' << n2 << '\n' << s1 << ' ' << s2 << ' ' << s3 << '\n'; for(auto p: m) std::cout << p.first << ' ' << p.second << '\n'; for(auto n: f.mem) std::cout << n << ' '; for(auto n: f.mem2) std::cout << n << ' '; }
Output:
world 0 1 1 abcd cd aa 1 a 2 abc 3 abcd 1 2 3 -1 -2 -3