std::result_of
From cppreference.com
Defined in header
<type_traits>
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template< class >
class result_of; //not defined |
(1) | (since C++11) |
template< class F, class... ArgTypes >
class result_of<F(ArgTypes...)>; |
(2) | (since C++11) |
Deduces the return type of a function call expression at compile time.
Contents |
[edit] Member types
Member type | Definition |
type
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the return type of the function F if called with the arguments ArgTypes...
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[edit] Possible implementation
template<class> struct result_of; template<class F, class... ArgTypes> struct result_of<F(ArgTypes...)> { typedef decltype( std::declval<F>()(std::declval<ArgTypes>()...) ) type; }; |
[edit] Examples
std::result_of
can be used to determine the result of invoking a functor, in particular if the result type is different for different sets of arguments:
#include <type_traits> struct S { double operator()(char, int&); float operator()(int); }; struct C { double Func(char, int&); }; int main() { // the result of invoking S with char and int& arguments is double std::result_of<S(char, int&)>::type f = 3.14; // f has type double static_assert(std::is_same<decltype(f), double>::value, ""); // the result of invoking S with int argument is float std::result_of<S(int)>::type d = 3.14; // f has type float static_assert(std::is_same<decltype(d), float>::value, ""); // result_of can be used with a pointer to member function as follows std::result_of<decltype(&C::Func)(C, char, int&)>::type g = 3.14; static_assert(std::is_same<decltype(g), double>::value, ""); }
[edit] See also
(C++11)
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obtains the type of expression in unevaluated context (function template) |