std::common_type
From cppreference.com
Defined in header
<type_traits>
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template< class... T >
struct common_type; |
(since C++11) | |
Determines the common type among all types T...
, that is the type all T...
can be implicitly converted to.
-
std::common_type
may be specialized for custom types, e.g. std::chrono::time_point. - For non-specialized
std::common_type
, the rules for determining the common type between every pairT1, T2
are exactly the rules for determining the return type of the ternary conditional operator whereT1
andT2
are the types of its second and the third operands. - For arithmetic types, the common type may also be viewed as the type of the (possibly mixed-mode) arithmetic expression such as T0() + T1() + ... + Tn().
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[edit] Member types
Name | Definition |
type
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the common type for all T...
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[edit] Specializations
Custom specializations of the type trait std::common_type are allowed. The following specializations are already provided by the standard library:
specializes the std::common_type trait (class template specialization) |
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specializes the std::common_type trait (class template specialization) |
[edit] Notes
With a single template argument, std::common_type<T>::type
is exactly T
, which makes it the C++ equivalent of boost::identity<T>
[edit] Possible implementation
template <class ...T> struct common_type; template <class T> struct common_type<T> { typedef T type; }; template <class T, class U> struct common_type<T, U> { typedef decltype(true ? declval<T>() : declval<U>()) type; }; template <class T, class U, class... V> struct common_type<T, U, V...> { typedef typename common_type<typename common_type<T, U>::type, V...>::type type; }; |
[edit] Examples
Demonstrates mixed-mode arithmetic on a user-defined class
#include <iostream> #include <type_traits> template <class T> struct Number { T n; }; template <class T, class U> Number<typename std::common_type<T, U>::type> operator+(const Number<T>& lhs, const Number<U>& rhs) { return {lhs.n + rhs.n}; } int main() { Number<int> i1 = {1}, i2 = {2}; Number<double> d1 = {2.3}, d2 = {3.5}; std::cout << "i1i2: " << (i1 + i2).n << "\ni1d2: " << (i1 + d2).n << '\n' << "d1i2: " << (d1 + i2).n << "\nd1d2: " << (d1 + d2).n << '\n'; }
Output:
i1i2: 3 i1d2: 4.5 d1i2: 4.3 d1d2: 5.8
Demonstrates the use as the identity template
#include <type_traits> #include <vector> #include <iostream> template <size_t N> void fun(const int (&a)[N]) { std::cout << "Array overload: "; for (int n: a) std::cout << n << ' '; std::cout << '\n'; } void fun(const std::vector<int>& v) { std::cout << "Vector overload: "; for (int n: v) std::cout << n << ' '; std::cout << '\n'; } int main() { fun( {1, 2, 3} ); // calls the vector overload fun( std::common_type<int[]>::type {1, 2, 3} ); // calls the array overload }
Output:
Vector overload: 1 2 3 Array overload: 1 2 3