std::make_move_iterator

From cppreference.com
Defined in header <iterator>
template< class Iterator >
std::move_iterator<Iterator> make_move_iterator( const Iterator& i );
(since C++11)

make_move_iterator is a convenience function template that constructs a std::move_iterator for the given iterator i with the type deduced from the type of the argument.

Contents

[edit] Parameters

i - input iterator to be converted to move iterator

[edit] Return value

A std::move_iterator which can be used to move from the elements accessed through i

[edit] Possible implementation

template< class Iterator >
std::move_iterator<Container> make_move_iterator( const Iterator& i )
{
    return std::move_iterator<Iterator>(i);
}

[edit] Example

#include <iostream>
#include <list>
#include <vector>
#include <string>
#include <iterator>
int main()
{
    std::list<std::string> s{"one", "two", "three"};
 
    std::vector<std::string> v1(s.begin(), s.end()); // copy
 
    std::vector<std::string> v2(std::make_move_iterator(s.begin()),
                                std::make_move_iterator(s.end())); // move
 
    std::cout << "v1 now holds: ";
    for(auto str : v1)
            std::cout << "\"" << str << "\" ";
    std::cout << "\nv2 now holds: ";
    for(auto str : v2)
            std::cout << "\"" << str << "\" ";
    std::cout << "\noriginal list now holds: ";
    for(auto str : s)
            std::cout << "\"" << str << "\" ";
    std::cout << '\n';
}

Output:

v1 now holds: "one" "two" "three"
v2 now holds: "one" "two" "three"
original list now holds: "" "" ""

[edit] See also

iterator adaptor which dereferences to an rvalue reference
(class template)
(C++11)
obtains an rvalue reference
(function template)