std::deque::erase

From cppreference.com

iterator erase( iterator pos );
iterator erase( const_iterator pos );
(1) (until C++11)
(since C++11)
iterator erase( iterator first, iterator last );
iterator erase( const_iterator first, const_iterator last );
(2) (until C++11)
(since C++11)

Removes specified elements from the container.

1) Removes the element at pos.

2) Removes the elements in the range [first; last).

All iterators and references are invalidated, unless the erased elements are at the end or the beginning of the container, in which case only the iterators and references to the erased elements are invalidated.

It is unspecified when the past-the-end iterator is invalidated. (until C++11).
The past-the-end iterator is also invalidated unless the erased elements are at the beginning of the container and the last element is not erased. (since C++11)

Contents

[edit] Parameters

pos - iterator to the element to remove
first, last - range of elements to remove

[edit] Return value

iterator following the last removed element.

[edit] Notes

All iterators must be valid and dereferenceable, that is, the end() iterator (which is valid, but is not dereferencable) cannot be used.

[edit] Example

#include <deque>
#include <iostream>
 
 
int main( )
{
    std::deque<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    c.erase(c.begin());
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
 
    c.erase(c.begin()+2, c.begin()+5);
 
    for (auto &i : c) {
        std::cout << i << " ";
    }
    std::cout << '\n';
}

Output:

0 1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9
1 2 6 7 8 9

[edit] Complexity

1) linear in the distance between position and last.

2) linear in distance between position and the end of the container.

[edit] See also

clears the contents
(public member function)