std::list::erase
From cppreference.com
iterator erase( iterator pos );
iterator erase( const_iterator pos ); |
(1) | (until C++11) (since C++11) |
iterator erase( iterator first, iterator last );
iterator erase( const_iterator first, const_iterator last ); |
(2) | (until C++11) (since C++11) |
Removes specified elements from the container.
1) Removes the element at pos
.
2) Removes the elements in the range [first; last)
.
References and iterators to the erased elements are invalidated. Other references and iterators are not affected.
Contents |
[edit] Parameters
pos | - | iterator to the element to remove |
first, last | - | range of elements to remove |
[edit] Return value
iterator following the last removed element.
[edit] Notes
All iterators must be valid and dereferenceable, that is, the end() iterator (which is valid, but is not dereferencable) cannot be used.
[edit] Example
#include <list> #include <iostream> #include <iterator> int main( ) { std::list<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; std::list<int>::iterator range_begin = c.begin(); std::list<int>::iterator range_end = c.begin(); std::advance(range_begin,2); std::advance(range_end,5); c.erase(range_begin, range_end); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; }
Output:
0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 6 7 8 9
[edit] Complexity
1) Constant.
2) linear in the distance between first
and last
.
[edit] See also
clears the contents (public member function) |