std::remove, std::remove_if
Defined in header
<algorithm>
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template< class ForwardIt, class T >
ForwardIt remove( ForwardIt first, ForwardIt last, const T& value ); |
(1) | |
template< class ForwardIt, class UnaryPredicate >
ForwardIt remove_if( ForwardIt first, ForwardIt last, UnaryPredicate p ); |
(2) | |
Removes all elements satisfying specific criteria from the range [first, last)
. The first version removes all elements that are equal to value
, the second version removes all elements for which predicate p
returns true.
Removing is done by shifting the elements in the range in such a way that elements to be erased are overwritten. Relative order of the elements that remain is preserved. Iterators pointing to an elements between the old and the new ends of the range are still dereferenceable, but the elements themselves have unspecified values. The function returns an iterator to the new end of the range.
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[edit] Parameters
first, last | - | the range of elements to process | |||||||||
value | - | the value of elements to remove | |||||||||
p | - | unary predicate which returns true if the element should be removed. The signature of the predicate function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. |
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Type requirements | |||||||||||
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ForwardIt must meet the requirements of ForwardIterator .
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-The type of dereferenced ForwardIt must meet the requirements of MoveAssignable .
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UnaryPredicate must meet the requirements of Predicate .
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[edit] Return value
Iterator to the new end of the range
[edit] Complexity
Exactly std::distance(first, last) applications of the predicate.
[edit] Notes
The similarly-named container member functions list::remove, list::remove_if, forward_list::remove, and forward_list::remove_if erase the removed elements.
[edit] Possible implementation
First version |
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template<class ForwardIt, class T> ForwardIt remove(ForwardIt first, ForwardIt last, const T& value) { ForwardIt result = first; for (; first != last; ++first) { if (!(*first == value)) { *result++ = *first; } } return result; } |
Second version |
template<class ForwardIt, class UnaryPredicate> ForwardIt remove_if(ForwardIt first, ForwardIt last, UnaryPredicate p) { ForwardIt result = first; for (; first != last; ++first) { if (!p(*first)) { *result++ = *first; } } return result; } |
[edit] Examples
The following code removes all spaces from a string by shifting all non-space characters to the left and then erasing the extra. This is an example of erase-remove idiom.
#include <algorithm> #include <string> #include <iostream> #include <ctype.h> int main() { std::string str1 = "Text with some spaces"; str1.erase(std::remove(str1.begin(), str1.end(), ' '), str1.end()); std::cout << str1 << '\n'; std::string str2 = "Text\n with\tsome \t whitespaces\n\n"; str2.erase(std::remove_if(str2.begin(), str2.end(), ::isspace), str2.end()); std::cout << str2 << '\n'; }
Output:
Textwithsomespaces Textwithsomewhitespaces
[edit] See also
copies a range of elements omitting those that satisfy specific criteria (function template) |